A 3-digit number is formed with digits 2, 5, 7 without repetition. How many even numbers can be formed?

A 3-digit number is formed with digits 2, 5, 7 without repetition. How many even numbers can be formed?

• A. 4
• B. 3
• C. 2
• D. 6

Answer: (C)

To form an even 3-digit number from the digits 2, 5, and 7 without repetition, the last digit must be even. The only even digit available is 2, so the last digit must be 2. The remaining two digits, 5 and 7, can be arranged in the first two positions in either order, giving two possibilities: 572 and 752. Therefore, there are 2 even numbers.

To form an even 3-digit number from the digits 2, 5, and 7 without repetition, the last digit must be even. The only even digit available is 2, so the last digit must be 2. The remaining two digits, 5 and 7, can be arranged in the first two positions in either order, giving two possibilities: 572 and 752. Therefore, there are 2 even numbers.